SIZING THE FLYWHEEL
We
now must determine how large a flywheel is needed to absorb this energy with an
acceptable change in speed. The change in shaft speed during a cycle is called
its
fluctuation (Fl)
and is equal to:
We
can normalize this to a dimensionless ratio by dividing it by the average shaft
speed. This ratio is called the
coefficient
of fluctuation (k)
.
This
coefficient of fluctuation
is a design parameter to be chosen by the
designer. It typically is set to a value between 0.01 and 0.05, which
correspond to a 1 to 5% fluctuation in shaft speed. The smaller this chosen
value, the larger the flywheel will have to be. This presents a design
trade-off. A larger flywheel will add more cost and weight to the system, which
factors have to be weighed against the smoothness of operation desired.
We
found the required change in energy
E
by integrating the torque
curve
and
can now set it equal to the right side of equation 9.14c (p. 254):
Factoring this expression:
If
the torque-time function were a pure harmonic, then its average value could be
expressed exactly as:
Our
torque functions will seldom be pure harmonics, but the error introduced by
using this expression as an approximation of the average is acceptably small.
We can now substitute equations 9.15b and 9.17 into equation 9.16c to get an
expression for the mass moment of inertia
Is
of the system
flywheel needed.
Equation
9.18 can be used to design the physical flywheel by choosing a desired
coefficient of fluctuation
k
, and using the value of
E
from
the numerical integration of the torque curve (see Table 9-3) and the average
shaft
to compute the needed system Is.
The physical flywheel’s mass moment of inertia If is
then set equal to the required system Is. But if the moments of inertia of the other
rotating elements on the same driveshaft (such as the motor) are known, the
physical flywheel’s required If
can be reduced by those
amounts.
The
most efficient flywheel design in terms of maximizing
If
for
minimum material used is one in which the mass is concentrated in its rim and
its hub is supported on spokes, like a carriage wheel. This puts the majority
of the mass at the largest radius possible and minimizes the weight for a given
If
. Even if a flat, solid circular disk flywheel
design is chosen, either for simplicity of manufacture or to obtain a flat
surface for other functions (such as an automobile clutch), the design should
be done with an eye to reducing weight and thus cost. Since in general
I = mr
2, a thin disk of large diameter will need fewer pounds of
material to obtain a given
I
than will a thicker disk of smaller diameter.
Dense materials such as cast iron and steel are the obvious choices for a
flywheel. Aluminum is not used. Though many metals (lead, gold, silver,
platinum) are more dense than iron and steel, their high cost prohibits use for
a flywheel.
Figure
9-26 shows the change in the input torque
T
12 for the
cam-follower system of Figure 9-25 after the addition of a flywheel sized to
provide a coefficient of fluctuation of 0.05. The oscillation in torque about
the unchanged average value is now 5%, much less than what it was without the
flywheel. The angular velocity of the shaft will also vary 5% as the flywheel
must change velocity to deliver and absorb energy as can be seen in equation
9.16b. A much lower power (non-servo) motor can now be used because the
flywheel is available to absorb the energy returned from the follower during
its cycle, though the added inertia of the flywheel will require sufficient
motor torque to accelerate it up to speed in a reasonably short time.
Copyright 2004, Industrial
Press, Inc., New York, NY